Math, asked by kapillokhande8, 11 months ago

A shopkeeper bought a radio and an usb speaker for rs 840 he sold them by making profit of 15percent on radio and 10 percentage on usb speeaker and he got profit of rs 102 find the difference between cost price of the radio and usb speaker

Answers

Answered by warylucknow
0

Answer:

The difference between cost price of the radio and USB speaker is Rs. 600.

Step-by-step explanation:

Let the cost price of radio be denoted by x and the cost of USB speaker be denoted by y.

The total cost price of radio and USB speaker is, x+y=840...(i)

The radio was sold a profit of 15% and the USB speaker at a profit of 10%.

The total selling price = SP of Radio + SP of USB

                                    =(x+15\%\ of\ x)+(y+10\%\ of\ y)\\=1.15x+1.10y

The profit earned was Rs. 120.

That is:

 Profit=Total\ SP-Total\ CP\\120=(1.15x+1.10y)-840\\1.15x+1.10y=960...(ii)

Solve (i) and (ii) simultaneously to determine the value of x and y as follows:

1.15x+1.10y=960\\\     x+\    y=840\\

Multiply (ii) by 1.15 as follows:

1.15x+1.10y=960\\1.15x+1.15y=966

Eliminate x by subtracting the two equations:

-0.05y=-6\\y=120

Substitute the value of y in (i) to determine the value of x as follows:

x+y=840\\x=840-y\\=840-120\\=720

The cost price of radio and USB speaker is Rs. 720 and Rs. 120 respectively.

The difference between cost price of the radio and USB speaker is:

x-y=720-120=600

Thus, the difference between cost price of the radio and USB speaker is Rs. 600.

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