A shopkeeper bought fertilizers worth Rs 8000 from the city and brought it to his village. He spent Rs 520 in transportation . If he wants to make an overall profit of 20% For jow much he should sell the whole materials.
Answers
Answer:
Step-by-step explanation:
total cost price of fertilizer = $ (8000+520)
= $ 8520
profit%= 20%
using the formula,
S.P.= {(100+P%)C.P.}/100
S.P. = {(100+20)8520}/100
S.P. = {120 X 8520}/100
S.P. = $10224
Thus selling price of fertilizer must be $10224
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Step-by-step explanation:
Given :-
A shopkeeper bought fertilizers worth Rs 8000 from the city and brought it to his village. He spent Rs 520 in transportation .
To find :-
If he wants to make an overall profit of 20% For how much he should sell the whole materials.?
Solution :-
Given that
The cost of fertilizers = Rs. 8000
Money spent on transport them = Rs. 520
Total Cost of fertilizers = 8000+520 = Rs. 8520
Cost Price = Rs. 8520
Desire profit on them = 20%
g % = 20%
We know that
Selling Price = [(100+g)/100]×Cost Price
=> Selling Price = [(100+20)/100]×8520
=> Selling Price = (120/100)×8520
=> Selling Price = (6/5)×8520
=> Selling Price = (6×8520)/5
=> Selling Price = 6×1704
=> Selling Price = 10224
Therefore,
Selling Price of the fertilizers = Rs. 10,224
Answer :-
The shopkeeper should sell the whole material for Rs. 10224
Check :-
SP = Rs. 10224
CP = Rs. 8520
Profit = Selling Price - Cost Price
=> Profit = 10224-8520
=> Profit = 1704
Now,
Profit Percentage = (Profit/CP)×100
=> P% = (1704/8520)×100
=> P% = (1/5)×100
=> P% = 100/5
=> P% = 20%
Verified the given relations in the given problem.
Used formulae:-
→ Selling Price = [(100+g)/100]×Cost Price
→ Profit = Selling Price - Cost Price
→ Profit Percentage = (Profit/CP)×100