Math, asked by dhanshreezanvar, 1 year ago

A shopkeeper bought some pencils at rupees 120 per dozen one day a poor boy came to the shopkeeper to buy two pencil but had only rupees 16 the shopkeeper gave him two pencil for rupees 16 find the selling price of pencil find the loss and loss percent of shopkeeper

Answers

Answered by akshay2002
1

C.P OF 12 PENCILS = 120 Rs

therefore for 1 pencil C.P = 120/12

=10 Rs

therefore C.P of 2 pencils = 2×10

= 20 Rs

S.P of Two pencils = 16 Rs

Loss = SP - CP

= 20-16

=4 Rs

loss % = Loss/CP ×100

=4/20×100

. =4 ×5

=20% loss

Hope my answer helps you if impressed tag my answer as brainliest

Answered by sumit755163
1

price of 1 pancile is 120/12 = 12

shopkeeper give him pancil par rupees 16/2 =8 .hence shopkeeper loss rs 4 per pancil hence shopkeeper loss 4×2= 8 and loss parsentage =8/24 × 100=33.33 %


dhanshreezanvar: Please tell me how 12 came and your answer is correct but write steps by step please
akshay2002: in question its given na 1 dozen and 1 dozen = 12
sumit755163: ok
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