a shopkeeper bought some sweet at 11 for 100 rupees later on he again bought an equal number of sweet at 10 for 100 rupees he sold all the sweets at 8 for 100 rupees find his again or loss on the whole transaction
Answers
Answered by
0
Step-by-step explanation:
he brought sweet at 11 and 10 for 100
total sweet 21 for 200(total cost)
cost of 1 sweet is 200/21 which is CP
now,
he sold them at 8 for 100
selling price of 1 sweet is 100/8=25/2
25/2 is greater than 200/21
hence there is a gain
gain=SP-CP
=25/2-200/11
=500/168(after simplifying
gain%=gain/CP × 100
500/168/200/21×100
=5/16×100
=31.25% gain
Answered by
6
To Find:-
his again or loss on the whole transaction
Solution:-
he brought sweet at 11 and 10 for 100
total sweet 21 for 200(total cost)
cost of 1 sweet is 200/21 which is CP
now,
he sold them at 8 for 100
selling price of 1 sweet is 100/8 = 25/2
25/2 is greater than 200/21
hence there is a gain
gain = SP-CP
= 25/2-200/11
= 500/168(after simplifying
gain% = gain/CP × 100
500/168/200/21×100
=5/16×100
=31.25% gain
Similar questions