Question

a shopkeeper bought two chairs rs 3120. he sold one of them at a gain of 36% but the other was sold for a loss of 15%. he found that each chair was sold for the same price. find the coast price of each chair.
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Answer 1

Answer:

$1032,2088$

Step-by-step explanation:

Given data:

• A shopkeeper bought two chairs for $3120$. He sold one of them at a gain of $36$% but the other was sold for a loss of $15%$%. He found that each chair was sold for the same price.

• Let the cost price of one chair be $x$.

• Then, the cost price of other chair is $3120-x$.

• According to the data given in the question,

$x+x\times\frac{36}{100} =(3120-x)-(3120-x)\times\frac{15}{100}$

$\frac{100x+36x}{100} =3120-x-3120\times\frac{15}{100} +\frac{15x}{100}$

$\frac{136x}{100} +x-\frac{15x}{100} =3120-468$

$\frac{136x+136s-15x}{100} =2652$

$\frac{257x}{100} =2652$

$x=1032$

• Cost price of other chair $=3120-1032=2088$

Hence, the cost price of two chairs be $1032$ and $2088$.

Answer 2

Given data,

A shop keeper bought two chairs at 3120 rupees.

Let the cost of first chair be $x$

Then the cost of second chair becomes $3120-x$

Also given that he sold first chair at $36$% profit

$x+x\times\frac{36}{100}$

Also he sold second chair at $15$% loss.

$(3120-x)-(3120-x)\times\frac{15}{100}$

The shop keeper find that each chair was sold at same price.

This means,

$x+x\times\frac{36}{100}=(3120-x)-(3120-x)\times\frac{15}{100}$

$\frac{100x+36x}{100} =\frac{100(3120-x)-(3120-x)15}{100}$

Hundred on both sides get cancelled.

$136x=312000-100x-46800+15x$

Transpose all $x$ terms to LHS and all constants to RHS.

$136x+100x-15x=312000-46800$

$236x-15x=265200$

$221x=265200$

$x=1200$

The cost of first chair is $1200$

The cost of second chair is $3120-x$

$3120-1200$

$1920$

The cost of second chair is $1920$

The cost of two chairs is $1200$ and $1920$