A shopkeeper bought two fans for ₹ 5000 he sold one at a profit of 10%and the other at a loss of 10% if the SP of both the the fans are equal find the cost price of each fan
Answers
The cost of one fan is Rs. 2250 and the cost of other fan is Rs. 2750.
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➛A shopkeeper bought two fans for ₹ 5000.
➛Sold one at a profit of 10%and the other at a loss of 10%.
➛The SP of both the the fans are equal.
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Cost price of each fan.
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We are given,
➛A shopkeeper bought two fans for ₹ 5000.
➛Sold one at a profit of 10%and the other at a loss of 10%.
➛The SP of both the the fans are equal.
Let the cost price of one fan be m.
Therefore, The cost price of other fan will be
Rs. ( 5000 - m ).
We know ,
so,
. ............... ( since SP = CP + Profit )
We are given that he sold the other fan at 10% loss.
We know ,
so,
. ............... ( since SP = CP - Loss)
According to given condition,
since, the SP of both fans is equal
Hence cost price of first fan is Rs. 2250
now cost price of second fan,
= 5000 - 2250
= 2750
hence, cost price of second fan is RS. 2750.
Answer: Cost Price Of The First Fan is Rs.2750 And The Cost Price Of The Second Fan is Rs.2250.
Step-by-step explanation:
CP of both fans => Rs.5000
Let the first fan be x. Let the second fan be y.
Profit % of x => 10%
Loss % of y => 10%
SP of X = SP of Y
5000/2 = 2500
Let this be the base.
10% of 2500 = 10/100 * 2500
= 250.
Now, to find for x and y.
2500+250= Rs. 2750 (Profit of 10%)
2500-250= Rs. 2250 (Loss of 10%)
Hope this helped y'all! <33