Math, asked by shinesaini8498, 2 days ago

A shopkeeper bought two phones at   ₹15,000 each. He sold one at a profit of 10% and the other at a loss of 10%. Find the overall profit or loss.​

Answers

Answered by manishaudugu
1

Answer:

Cost price of a two phones =Rs 15,000

profit =10%

Selling price =[100+p/100]×C.P

=[100+10/100]×10000

=110/100×15,000

=11×15000

=Rs. 165000

Loss =10%

Selling price =[100−L/100]×C.P

=100−10/100×15,000

=90/100×15,000

=9×1500

=13500

Total cost price =165000+13500 =178500

Total selling price =165000+13500=178500

Here C.P=S.P

Therefore, it is neither Loss nor Profit.

Answered by manjusha9687
0

Answer:

Answer:

0 profit or loss

Step-by-step explanation:

The shopkeeper gained a profit of 10%.

And also had a loss of 10%.

So his profit or loss was 0%

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