A shopkeeper bought two phones at ₹15,000 each. He sold one at a profit of 10% and the other at a loss of 10%. Find the overall profit or loss.
Answers
Answered by
1
Answer:
Cost price of a two phones =Rs 15,000
profit =10%
Selling price =[100+p/100]×C.P
=[100+10/100]×10000
=110/100×15,000
=11×15000
=Rs. 165000
Loss =10%
Selling price =[100−L/100]×C.P
=100−10/100×15,000
=90/100×15,000
=9×1500
=13500
Total cost price =165000+13500 =178500
Total selling price =165000+13500=178500
Here C.P=S.P
Therefore, it is neither Loss nor Profit.
Answered by
0
Answer:
Answer:
0 profit or loss
Step-by-step explanation:
The shopkeeper gained a profit of 10%.
And also had a loss of 10%.
So his profit or loss was 0%
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