A shopkeeper bought two phones for Rs. 8,000 each. After selling the
phones, there was a loss of 4% on the 1st phone while a profit of 8% on the
2nd phone. Calculate the overall gain or loss per cent on the whole
transaction.
Answers
Step-by-step explanation:
SP of first phone = 8000×96/100= 7680
SP of second phone= 8000×108/100= 8640
CP of both phones = 8000+8000= 16000
Total SP = 7680+8640= 16320
As SP is greater than cp ,therefore there will be profit
Profit%=( SP-CP/CP)×100
(320/16000)×100
2%
Answer:
2% profit
Step-by-step explanation:
As the shopkeeper bought both phones at Rs. 8000 each.
Total cost price = Rs. 16,000
Assume that the cost price of the 1st phone is Rs. 100
Consider the deal of phone 1,
As it is given, there is 4% loss, the selling price will be = Rs. 96
For CP = 100, SP = 96
So, for CP = 1, SP = 96/100
Now, given, CP = 8000
Hence, SP = 96/100 × 8000 = 7680
so the selling price of 1st phone = Rs. 7680
Consider the deal of phone 2, there is an 8% profit.
Hence, the selling price will be = Rs. 108
For CP = 100, SP = 108
So, for CP = 1, SP = 108/100
Now, given CP = 8000
hence, SP = 108/100 × 8000 = 8640
Thus, the selling price of 2nd phone = Rs. 8640
Here, the total selling price will be = Rs. 7680 + Rs. 8640 = 16320
Now, it can be seen that,
Total selling price > total cost price i.e. Rs. 16320 > Rs. 16000
, there is a profit of Rs. (16320 – 16000) = Rs. 320
the overall profit percentage will be-
Profit% = (Profit/Total Cost Price) × 100 = (320/16000) × 100 = 2
Thus, there is a total of 2% profit for the whole transaction.