A shopkeeper bought two phones for Rs. 8,000 each. After selling the phones, there was a loss of 4% on the 1st phone while a profit of 8% on the 2nd phone. Calculate the overall gain or loss per cent on the whole transaction.
Answers
Answer:
SP OF 1ST PHONE = 8000(1-4/100)
= 8000(96/100) = 7680 RS
SP OF 2ND PHONES = 8000(1+8/100)
= 8000(108/100) = 8640
CP OF 2 PHONES = 16,000 RS
SP OF 2 PHONES = 7680 + 8640
= RS 16,320
PROFIT OF 320 RS
P% = 320/16000 × 100 = 2%
Step-by-step explanation:
Please mark me as brainliest!!
Answer:
As the shopkeeper bought both phones at Rs. 8000 each.
Total cost price = Rs. 16,000
Assume that the cost price of the 1st phone is Rs. 100
Consider the deal of phone 1,
As it is given, there is 4% loss, the selling price will be = Rs. 96
For CP = 100, SP = 96
So, for CP = 1, SP = 96/100
Now, given, CP = 8000
Hence, SP = 96/100 × 8000 = 7680
so the selling price of 1st phone = Rs. 7680
Consider the deal of phone 2, there is an 8% profit.
Hence, the selling price will be = Rs. 108
For CP = 100, SP = 108
So, for CP = 1, SP = 108/100
Now, given CP = 8000
hence, SP = 108/100 × 8000 = 8640
Thus, the selling price of 2nd phone = Rs. 8640
Here, the total selling price will be = Rs. 7680 + Rs. 8640 = 16320
Now, it can be seen that,
Total selling price > total cost price i.e. Rs. 16320 > Rs. 16000
, there is a profit of Rs. (16320 – 16000) = Rs. 320
the overall profit percentage will be-
Profit% = (Profit/Total Cost Price) × 100 = (320/16000) × 100 = 2
Thus, there is a total of 2% profit for the whole transaction.