Question

A shopkeeper bought two radio for rs 1008,he sold at a loss 20perc and other at profit of 44per if he sell both radio at same price then find cost price of the radio which sold at loss

Answer 1

The cost price of the radio which sold at loss is Rs. 648.

Explanation

A shopkeeper bought two radio for Rs. 1008

Suppose, the cost price of the first radio is  $x$ rupees

So, the cost price of the second radio will be:  $(1008-x)$ rupees.

The shopkeeper sold the first radio at a loss of 20% . So, the selling price of first radio will be:  $(x-0.20x)rupees = 0.80x$ rupees.

He sold the second radio at a profit of 44%. So, the selling price of the second radio will be:  $[(1008-x)+0.44(1008-x)]$ rupees.

As he sold both radio at same price, so the equation will be......

$0.80x=(1008-x)+0.44(1008-x)\\ \\ 0.80x=1008-x+443.52-0.44x\\ \\ 0.80x= 1451.52-1.44x\\ \\ 0.80x+1.44x=1451.52\\ \\ 2.24x=1451.52\\ \\ x=\frac{1451.52}{2.24}=648$

So, the cost price of the radio which sold at loss is Rs. 648.

Answer 2

Answer:

Step-by-step explanation:if the radio is ₹800and sold it for 600.calculate it's loss