Math, asked by vishalchaudharu8030, 10 months ago

A shopkeeper buy 12 kg tea of one quality at the rate of ₹250 per kg and 18 kg tea of another equality at the rate of ₹300 per kg. he mixes them and sells at the rate of ₹2900 per kg. find his gain or loss%? for class 7

Answers

Answered by lchkashyap2005
5

Answer:

bro it has two answers ok first listen don't quit the answer

1st ans : gain % = 935.7%

2nd ans : gain% = 3.57%

Step-by-step explanation:

AS PER QUESTION:

shopkeeper buys 12kgs of tea for ₹250

so, 12*250=₹3000

again shopkeeper buys 18kgs of tea for ₹300

so, 18*300=₹5400

sum of these two = 12kg+18kg=₹3000+₹5400=₹8400 for total 30kgsafter mix,

shop keeper sells ₹2900/kg

so, 2900*30=₹87000so,

we get profit = sp-cp=87000-8400=₹78600

so, let's find out,

gain percentage = profit*100/cp

= 78600*100/8400

=935.7%

BUT ONCE THINK LIKE A MISTAKER I THOUGHT THATBUT ONCE THINK LIKE A MISTAKER I THOUGHT THATYOU HAVE MISTAKEN THE QUESTION IT'S NOT 2900/KG IT'S 290/KG LET'S SEE THE ANSWER :

shopkeeper buys 12kgs of tea for ₹250

so, 12*250=₹3000

again shopkeeper buys 18kgs of tea for ₹300

so, 18*300=₹5400

sum of these two = 12kg+18kg=₹3000+₹5400=₹8400 for total 30kgsafter mix,

shop keeper sells ₹290/kg

so, 290*30=₹8700so,

we get profit = sp-cp=8700-8400=₹300

so, let's find out,

gain percentage = profit*100/cp

= 300*100/8400

=3.57%

Similar questions