A shopkeeper buys a certain number of books for Rs.960. If the cost per book was Rs.8 less, the number of books that could be bought would be 4 more. Write an equation taking the original cost of each book as Rs.x and solve it to find the value the original cost of the books.
Answers
Answer:
Rs 48
Step-by-step explanation:
Hi,
Let 'x' be the cost price of 1 book
Given that total books cost Rs 960
Number of books he had bought ,N = 960/x------(1)
Given that if the cost per book was Rs.8 less, the number of books that
could be bought would be 4 more
N + 4 = 960/(x - 8)------(2)
Solving (1) and (2), we get
960/x + 4 = 960/(x - 8)
On simplifying we get
x² - 8x - 1920 = 0
(x - 48)*(x + 40) = 0
x = 48
Hence, Original Cost of each book = Rs 48
Hope, it helps !
Answer:
Step-by-step explanation:
Let the number of book bought by the shopkeeper be x and the cost per book be y.
Then we can write (x * y) = Rs 960
or, xy = 960.------------(i)
If the cost per book was Rs.8 less i.e. (y - 8), then 4 more books could be bought.
i.e. (y - 8) * ((x + 4) = Rs 960.
or, (xy - 8x + 4y - 32) = 960 ------------ (ii)
Putting the value of xy we get,
960 - 8x + 3840/x - 32 = 960
or, 8x² + 32x - 3840 = 0.
or, x² + 4x - 480 = 0
or, x² + 24x - 20x - 480 = 0
or, x(x + 24) - 20(x + 24) = 0
or, x = 20 as it cannot be negative.
Therefore, no.of books purchased = 20.
Cost of each book = 960/20 = Rs 48.