a shopkeeper buys a number of books for rs 80 if he had bought 4 more books for the same amount it books would have cost rupees 1 less how many books did he buy
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Let the number of books = x
Amount for x books = ₹80
80/x
If he buys 4 more books = x+4
80/x+4
So,
80/x - 80/x+4 = 1
x=16 and not -20 because number of books cannot be -ve.
number of books bought = x+4
=16+4 = 20books
Therefore, he bought 20books.
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Eq no 1:- total books purchased = x
Therefore unit price = 80/ x
Eq no 2:- 4 extra book purchased on same price = ×+4 =80
Therefore unit price = 80/(×+4)
Difference of price is Rs. 1
Hence 80/× - 80/(x-4) =1
By solving the equation
320/ (xpower2 + 4x)=0
Xpower2+4x-320=0
X(X+20) -16(X+20)=0
(X+20) (X-16)=0
X=-20, X=16
We negate negative answer
Therefore no of books brought =16
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