A shopkeeper buys a number of books rupees 800. If he had bought 4 more books for the same amount is book would have cost him rupees 10 less . How many books did you buy?
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Answered by
176
Let the number of books purchased for ₹ 800 be x
Then , cost of each book= ₹ 800/x……..(1)
If he buys 4 more books, then number of books= x+4
Cost of each book= ₹ 800/(x+4)..........(2)
A.T.Q
800/x - 800/(x+4)= 10
(800x+ 3200-800x)/x(x+4)= 10
3200= 10x(x+4)
3200= 10x²+40x
10x²+40x=3200
10x²+40x-3200=0
10( x²+4x-320)=0
x²+4x-320=0
x²+20x-16x-320=0
x(x+20)-16(x+20)=0
(x+20) (x-16)=0
x+20=0 or x-16=0
x= -20 or x= 16
[Numbers of books cannot be negative]
Neglecting x=-20, we get x=16
Hence, number of books purchased =16
HOPE THIS WILL HELP YOU.....
Then , cost of each book= ₹ 800/x……..(1)
If he buys 4 more books, then number of books= x+4
Cost of each book= ₹ 800/(x+4)..........(2)
A.T.Q
800/x - 800/(x+4)= 10
(800x+ 3200-800x)/x(x+4)= 10
3200= 10x(x+4)
3200= 10x²+40x
10x²+40x=3200
10x²+40x-3200=0
10( x²+4x-320)=0
x²+4x-320=0
x²+20x-16x-320=0
x(x+20)-16(x+20)=0
(x+20) (x-16)=0
x+20=0 or x-16=0
x= -20 or x= 16
[Numbers of books cannot be negative]
Neglecting x=-20, we get x=16
Hence, number of books purchased =16
HOPE THIS WILL HELP YOU.....
MdAnas1:
nice solution
Answered by
22
Answer:Let the number of books purchased for ₹ 800 be x
Then , cost of each book= ₹ 800/x……..(1)
If he buys 4 more books, then number of books= x+4
Cost of each book= ₹ 800/(x+4)..........(2)
A.T.Q
800/x - 800/(x+4)= 10
(800x+ 3200-800x)/x(x+4)= 10
3200= 10x(x+4)
3200= 10x²+40x
10x²+40x=3200
10x²+40x-3200=0
10( x²+4x-320)=0
x²+4x-320=0
x²+20x-16x-320=0
x(x+20)-16(x+20)=0
(x+20) (x-16)=0
x+20=0 or x-16=0
x= -20 or x= 16
[Numbers of books cannot be negative]
Neglecting x=-20, we get x=16
Hence, number of books purchased =16
HOPE THIS help u....
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