A shopkeeper buys a number of packets of biscuits for rs 80.If he had bought 4 more packets for he same amount each packet would have cos rs 1 less. How many pakets did he buy
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let he buys x packets for Rs 80
so cost of each packet =Rs 80/x
now he bought 4 more packets for the same amount,
so each packet cost=Rs 80/(x+4)
as per question 80/x-80/(x+4)=1
or 80[x+4-x]/[x(x+4)]=1
or 80*4=x(x+4)=x^2+4x
or x^2+4x-320=0
or x^2+20x-16x-320=0
or x(x+20)-16(x+20)=0
or (x+20)(x-16)=0
or x=-20 or 16
taking the positive value he bought 16 packets
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so cost of each packet =Rs 80/x
now he bought 4 more packets for the same amount,
so each packet cost=Rs 80/(x+4)
as per question 80/x-80/(x+4)=1
or 80[x+4-x]/[x(x+4)]=1
or 80*4=x(x+4)=x^2+4x
or x^2+4x-320=0
or x^2+20x-16x-320=0
or x(x+20)-16(x+20)=0
or (x+20)(x-16)=0
or x=-20 or 16
taking the positive value he bought 16 packets
Please mark brainlist
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