Question

A shopkeeper buys an article for ₹ 600 and marks 25% above the cost price. Find (i) the selling price if he sells the article at 10% discount; (ii) the percentage of discount if it is sold for ₹ 690.

Answer 1

CP of article=600

MP of the article=600(1+25/100)=600*5/4=750

SP of the article=750(1-10/100)=750*9/10=675

if the SP is 690, then discount=750-690=60

% of discount=60/750*100=8%

Answer 2

Answer:

(i) 675 Rs.

(ii) 8%

Step-by-step explanation:

According to the question

Cost price of an article = 600 Rs.

and shopkeeper marked it 25 % above the cost price.

So,

mark price = $600\ +\ 600\times\frac{25}{100}$

                  = 600 + 6 x 25

                  = 600 + 150

                  = 750 Rs.

(i) we have to find the selling price of article at 10% discount.

we know that ,

selling price = $(\frac{100\ -\ discount\%}{100})\times mark\ price$

                     = $\frac{90}{100}\times750$

                     = 9 x 75

                     = 675 Rs. (Answer)

(ii) Now we are to find the percentage of discount if selling price will be 690 Rs.

suppose discount percentage is x.

As we know that,

$mark\ price\times\frac{100 - discount\%}{100} = selling\ price$

$750\times\frac{100\ -\ x}{100} = 690$

$100\ -\ x = \frac{690\times100}{750}$

100 - x = 92

100 - 92 = x

∴ x = 8 % (Answer)