a shopkeeper buys some books for rs 80.if he buys 4more books at this price wht is the price for one book if it is 1 less for each
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Answer: 16 books
Step-by-step explanation:
Let the number of books purchased for Rs.80 = x
Then cost of each books = 80/x
If he buys for more books, the number of books = x+4
Cost of each book = 80/x+4
(80/x)-[80/(x+4)]=1
Solve x=-20 and x = 16
Rejecting x = -20
The number of books purchased = 16
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let price of each book is X
number of books = 80/X
ATQ
80/(X-1) = 80/X +4
{80/(X-1)} - (80/X) =4
80X- 80X+80 = 4(x^2-X)
X^2-2X=20
X^2-X-20=0
X^2- 5X+4X-20=0
X(X-5) +4(X-5)
(X+4)(X-5)
X=5
So price of each book is 5 rupees .
number of books = 80/X
ATQ
80/(X-1) = 80/X +4
{80/(X-1)} - (80/X) =4
80X- 80X+80 = 4(x^2-X)
X^2-2X=20
X^2-X-20=0
X^2- 5X+4X-20=0
X(X-5) +4(X-5)
(X+4)(X-5)
X=5
So price of each book is 5 rupees .
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