Question

A shopkeeper buys some pen worth RS 662.50 and sales pens Worth Rs 387.50 at the Cost Price .If he buys minimum number of pens then how many pens are remaining?
a)18
b)19
c)20
d)26

Answer 1

Answer:

Let the CP of each pen be Rs.x.

Then,

CP of 5 pens=Rs. 5

SP of 5 pens=CP of 7 pens=Rs. 7

now,gain=SP-CP=Rs.(7-5)=Rs. 2

gain%=gain/cp*100

=(2/5 *100)%= 40%

Hence,the gain=40%.

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Answer 2

Correct Options:

a) 18 b) 19 c) 22 d) 26.

Answer:

If the shopkeeper buys the minimum number of pens then 22 pens are remaining. Option c) 22 is the correct answer.

Given:

The cost price for a total of n pens is Rs. 662.50.

The selling price for sold pens is Rs. 387.50.

To find:

The number of pens remaining needs to be determined.

Solution:

Let's C.P. of 1 pen = x.

If there are n pens available then C.P of n pens = Rs. 662.50.

This Rs. 662.50 as well as Rs. 387.50 should be multiple of a number such that a fixed number of pens is obtained that is not in decimal and is not an approximate number.

So, suppose 12.5 is a number that is a multiple of  Rs. 662.50 as well as Rs. 387.50.

So, let it is divisible by 12.5.

⇒ $\frac{662.50}{12.5}$ = 53 numbers.

53 = n is the total number of pens available.

This means the value of n = 53 and the C.P. of 1 pen = x = Rs. 12.5.

Sold-out pens = $\frac{387.50 }{12.5}$ = 31 numbers.

So, the remaining pens will be equal to the (Total number of pens - Sold-out pens).

⇒ 53-31 = 22 pens.

Therefore, 22 pens are remaining. Hence, option (c) is correct.

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