Question

A shopkeeper claims to sell his goods at x% loss but uses 30% less weight and indeed gains a profit of 40% If he had also cheated by 40% while buying then find the actual profit?? ​

Answer 1

Given :  A shopkeeper claims to sell his goods at x% loss but uses 30% less weight and indeed gains a profit of 40% . he had also cheated by 40% while buying

To find : Value of x  & actual profit

Step-by-step explanation:

Let say Cost Price = C  Rs

x % Loss => Sell Price = C -  xC/100  Rs

Uses 30% less weight => actual cost price = C - (30/100)C = 0.7C  Rs

Profit of 40 %  =  (40/100)0.7C  = 0.28C

Selling Price = 0.7C + 0.28C = 0.98C

0.98C = C -  xC/100

=> xC/100 = 0.02C

=> x = 2 %

x  = 2  

Cost Price = 0.7C      Sell price  =  0.98C

cheated by 40% in weight

=> in 0.7C  he got  1.4

=> 1 got in  0.7C/1.4  = 0.5C

Cost Price = 0.5C

Selling Price = 0.98C

Profit = 0.98C - 0.5C = 0.48C

Profit % = (0.48C/0.5C) * 100   = 96%

x = 2  , actual Profit = 96 %

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