Question

A shopkeeper decides to sell a certain item at a certain price. He marks the price of the item, by increasing the decided price by 30%. While selling the item, he offers 20% discount.Find how many percent he gets more on the decided price.

Answer 1

Let decided price be x
then,

$x \times \frac{130}{100} = mrp \\ discount \: = \: 20\% \\ so. \\ \frac{130x}{100} \times \frac{100}{80} = \frac{13x}{8} = \frac{13}{8} x$

Now,
he sold that item at ₹ 13/8 x.

And we know that,

$profit \: = \: sp \: - \: cp \\ profit \: = \\ = \: \frac{13x}{8} - x \\ = \frac{13x - 8x}{8} \\ = \frac{5x}{8} \\ profit \: = \: \frac{5x}{8}$

Profit % =
$= \frac{profit}{cp} \times 100 \\ = \frac{ \frac{5x}{8} }{x} \times 100 \\ = \frac{5x}{8x} \times 100 \\ = \frac{5}{8} \times 100 \\ = 2.5 \times 5 \\ = 12.5\%$
•••••

12.5 % he gets more on the decided price.

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Answer 2

Answer:

Hey her is your answer mate

Let the decided price of the item be ₹ 100.

∴ Marked price of the item = ₹ 100 + 25% of ₹ 100 = ₹ 100 + ₹ 25 = ₹ 125

Discount on the item = 20% of ₹ 125 = 20/100×125 = ₹ 25

∴ Selling price of the item = Marked price of the item − Discount on the item = ₹ 125 − ₹ 25 = ₹ 100

Since the decided price of the item is same as the selling price of the item so the shopkeeper neither makes any profit nor any loss on selling the item.

Thus, the shopkeeper gets 0% on the decided price.