Math, asked by kalpanavermajaipur, 8 months ago

A shopkeeper eams a profit of 1 by selling a pencil and incurs a loss of 20 paise by selling an
ett
na given day, he incurs an overall loss of 10. On this day, he sold 35 pencils. How many
erasers were sold on this day?
Next day, he earned a profit of 25. On this day, he sold 100 erasers. How many pencils did
he sell

Answers

Answered by sneha193262
0

Answer:

(i) let no. of eraser sold be x

(i) let no. of eraser sold be xtotal loss = rs 10

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -35

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10x

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be y

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 25

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 2525= profit by pencil - loss by eraser

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 2525= profit by pencil - loss by eraser25=( 1× y) - (100× 0.10)

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 2525= profit by pencil - loss by eraser25=( 1× y) - (100× 0.10)25=y-10

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 2525= profit by pencil - loss by eraser25=( 1× y) - (100× 0.10)25=y-1035=y

(i) let no. of eraser sold be xtotal loss = rs 1010= loss by eraser - profit by pencil10= (0.10x) - (35×1)10= 0.10x -3545=0.10xx=450so 450 erasers were sold that day(ii) let no. of pencil be ytotal profit = rs 2525= profit by pencil - loss by eraser25=( 1× y) - (100× 0.10)25=y-1035=yso 35 pencils were sold that day

Hope it'll help uh.....!!

Answered by Anonymous
2

Answer:

this is the right answer mention in above

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