Question

A shopkeeper earns a profit of 15% on selling a radio whereas if it sold for rs 360 less he suffers a loss of 15%. What is the cost price of the radio for the shopkeeper?

Answer 1

Let CP of radio be 'x' and SP of radio be 'y'.
Then ,
profit=SP-CP=y-x
given that,
profit%=15%
We know that,
profit%=(profit/CP)×100

15={(y-x)/x}×100

15x=100y-100x

115x=100y

23x=20y

x=20y/23..........................................1
If the shopkeeper sells the radio for Rs 360 less then the loss occured is of 15%.
Now we have,
SP=y-360
CP=x
loss=CP-SP=x-(y-360)
loss=x-y+360
loss%=15%
we know that,
loss%=(loss/CP)×100

15={(x-y+360)/x}×100

15x=100x-100y+36000

-85x=-100y+36000
Putting eq1 in above equation we get,
-85{20y/23}=-100y+36000

-1700y=-2300y+828000

600y=828000

y=828000/600

y=1380
Now by putting value of y in eq1 we get,
x=(20×1380)/23

x=1200

Hence CP of radio for the shopkeeper=Rs1200

Answer 2

answer is 1200 pls mark me as brainlist