Question

A shopkeeper earns a profit of ₹2 by selling a pen and incurs a loss of 50 p per pencil and loss of 15 p per eraser while selling pencils and erasers of old stock. On a particular day, he earns a profit of ₹10. If he sold 10 pens and the nom of pencils and erasers he sold are in ratio 7:10,then find the no. of pencils and erasers he sold on that day.

Plz solve it step by step...​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Number of penciles =7×2=14

Number of penciles =7×2=14and number of erasers =10×2=20

Step-by-step explanation:

By selling a pen gain is Rs.2

and by selling a pencils, he loses 50 paise

and an eraser, he loses 15 paise

On one day, he gain =Rs.10

On that day he sold 10 pens and pencils and erasers in the ratio of 7:10

On ten pens, his gain =10×2=Rs.20

loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise

Ratio in pencil and eraser =7:10

Let number of pencils =7x, then eraser =10x

7x×50+10x×15=1000

⇒350x+150x=1000

⇒500x=1000

⇒x=2

Number of penciles =7×2=14

and number of erasers =10×2=20