Math, asked by goyalnikka, 11 months ago

A shopkeeper earns a profit of ₹30 by selling one geometry box and incurs a loss of ₹10 while selling one lunch box.
(a) In a month, he earns neither profit nor loss. lf he sold 60 lunch boxes, how many geometry boxes did he sell?
(b) In the next month, he incurs a loss of ₹50. ln this period, if he sold 12 geometry boxes, how many lunch boxes did he sell?​

Answers

Answered by dogra150
0

Answer:

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Answered by mishra96250
1

Answer:a)20

Loss on 60 Lunch Box-

60×10=600(as loss is per lunch box Rs10)

As per condition we will have to sell 20 geometry box(as there is a profit of 30 per geometry box)

30×20=600

B)41

Profit on 12 geometry box =12×30=360

To fullfill the condition we will required to sell 41 lunch box(as loss is to be Rs 50)

41×10=410(loss)

12×30=360(profit) Difference (410-360)=50

Step-by-step explanation:

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