A shopkeeper earns a profit of ₹30 by selling one geometry box and incurs a loss of ₹10 while selling one lunch box.
(a) In a month, he earns neither profit nor loss. lf he sold 60 lunch boxes, how many geometry boxes did he sell?
(b) In the next month, he incurs a loss of ₹50. ln this period, if he sold 12 geometry boxes, how many lunch boxes did he sell?
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Answer:a)20
Loss on 60 Lunch Box-
60×10=600(as loss is per lunch box Rs10)
As per condition we will have to sell 20 geometry box(as there is a profit of 30 per geometry box)
30×20=600
B)41
Profit on 12 geometry box =12×30=360
To fullfill the condition we will required to sell 41 lunch box(as loss is to be Rs 50)
41×10=410(loss)
12×30=360(profit) Difference (410-360)=50
Step-by-step explanation:
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