Question

A shopkeeper earns a profit of ₹30 by selling one geometry box and incurs a loss of ₹10 while selling one lunch box.
(a) ln a month, he earns neither profit nor loss. If he sold 60 lunch boxes, how many geometry boxes did he sell?
(b) In the next month, he incurs a loss of ₹50. In this period, if he sold 12 geometry boxes, how many lunch boxes did he sell?​

Answer 1

Answer: he sells 20 geometry boxes in first month and 31 lunch boxes in second month.

Step-by-step explanation:

(i) Let required geometry boxes be x.

Then, profit will 30x

A/q

Profit = loss

=> 30x = 10 ×60

=> x= 10 × 60/30

=> x= 20

Therefore, 20 geometry boxes sold first month.

(ii) Now,

Let required lunch boxes sold in second month be x.

Then, loss will 10y

A/q

Profit = loss +50

=> 12×30 = 10y+50

=> 10y = 360-50

=> y= 310/10

=> y = 31

Therefore, no. Of lunch boxes sold in second month is 31.

Hope, this will help you.