Math, asked by suryadevkumar050, 6 days ago


A shopkeeper earns a profit of 5 by selling a new register and incurs a loss of 2 per register on old stock. In a particular day, he incurs a loss of 6, by selling 10 new registers. How many old registers did he sell on that particular day? ​

Answers

Answered by hrwt001
2

43 old registers were sold on a particular day.

Step-by-step explanation:

Let's assume the loss from sale of old regiters be"x"

Profit on selling 10 NEW registers = Rs. 50

Total Loss = Rs. 36

So, total Loss = Loss from Old Registers - Profit from New Registers

⇒ 36 = x - 50

⇒ x = 86

So, loss from old registers is Rs. 86, however loss from one old register is Rs. 2.

Hence total old registers sold = 86/2 = 43 old registers

Answered by Anonymous
0

Step-by-step explanation:

Solution:

Let assume the loss from sale of old regiters be \x

profit on selling 10 New registers =\50 Rs.

Total loss =36 Rs.

So , Total loss = Loss from old resisters - profite from new registers

\ Rightarrow 36=x-50Rightarrow x=86

So , loss from old register is 86 Rs. , however loss from one old register is 2 Rs.

Hence total old registers sold= 86/2=43 old registers

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