A shopkeeper earns a profit of 5 by selling a new register and incurs a loss of 2 per register on old stock. In a particular day, he incurs a loss of 6, by selling 10 new registers. How many old registers did he sell on that particular day?
Answers
43 old registers were sold on a particular day.
Step-by-step explanation:
Let's assume the loss from sale of old regiters be"x"
Profit on selling 10 NEW registers = Rs. 50
Total Loss = Rs. 36
So, total Loss = Loss from Old Registers - Profit from New Registers
⇒ 36 = x - 50
⇒ x = 86
So, loss from old registers is Rs. 86, however loss from one old register is Rs. 2.
Hence total old registers sold = 86/2 = 43 old registers
Step-by-step explanation:
Solution:
Let assume the loss from sale of old regiters be \x
profit on selling 10 New registers =\50 Rs.
Total loss =36 Rs.
So , Total loss = Loss from old resisters - profite from new registers
\ Rightarrow 36=x-50Rightarrow x=86
So , loss from old register is 86 Rs. , however loss from one old register is 2 Rs.
Hence total old registers sold= 86/2=43 old registers