A shopkeeper earns a profit of 5 by selling
a notebook and incurs a loss of 50 paise per
pencil and eraser while selling these from the
old stock. On a particular day, she earns a
profit of 30. If she sold 10 notebooks and
the number of pencils and erasers she sold are
in the ratio of 6:4, then find the number of
pencils and erasers she sold on that day.
Answers
Answer:
hey
Step-by-step explanation:
By selling a pen gain is Rs.2
and by selling pencils, he loses 50 paise
and an eraser, he loses 15 paise
On one day, he gains =Rs.10
On that day he sold 10 pens and pencils and erasers in the ratio of 7:10
On ten pens, his gain =10×2=Rs.20
loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise
the Ratio in pencil and eraser =7:10
Let the number of pencils =7x, then eraser =10x
7x×50+10x×15=1000
⇒350x+150x=1000
⇒500x=1000
⇒x=2
Number of pencils =7×2=14
and number of erasers =10×2=20
hope it helps
mark as brainlist
By selling a pen gain is Rs.2
and by selling pencils, he loses 50 paise
and an eraser, he loses 15 paise
On one day, he gains =Rs.10
On that day he sold 10 pens and pencils and erasers in the ratio of 7:10
On ten pens, his gain =10×2=Rs.20
loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise
the Ratio in pencil and eraser =7:10
Let the number of pencils =7x, then eraser =10x
7x×50+10x×15=1000
⇒350x+150x=1000
⇒500x=1000
⇒x=2
Number of pencils =7×2=14
and number of erasers =10×2=20
hope it helps
mark as brainlist