Math, asked by subodhk1986, 1 month ago

A shopkeeper earns a profit of 5 by selling a notebook and incurs a loss of 50 paise per pencil and eraser while selling these from the old stock. On a particular day, she earns a profit of 30. If she sold 10 notebooks and the number of pencils and erasers she sold are in the ratio of 6:4, then find the number of pencils and erasers she sold on that day.

the answer has to come 24 pencils and 16 erasers.

Give me full process.

Those who will give the answer correctly I will mark the brainliest, I will vote, I will give thanks and I will follow.
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Answers

Answered by vikashpatnaik2009
0

Answer:

By selling a pen gain is Rs.2

and by selling a pencils, he loses 50 paise

and an eraser, he loses 15 paise

On one day, he gain =Rs.10

On that day he sold 10 pens and pencils and erasers in the ratio of 7:10

On ten pens, his gain =10×2=Rs.20

loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise

Ratio in pencil and eraser =7:10

Let number of pencils =7x, then eraser =10x

7x×50+10x×15=1000

⇒350x+150x=1000

⇒500x=1000

⇒x=2

Numbe rof penciles =7×2=14

and number of erasers =10×2=20

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