Math, asked by vilmaramesh90, 3 days ago

A shopkeeper earns a profit of Re 1 by selling one pen and incurs a loss of 40 paise per pencil

while selling pencils of her old stock. (i) In a particular month she incurs a loss of Rs 5. In this

period, she sold 45 pens. How many pencils did she sell in this period? (ii) In the next month she

earns neither profit nor loss. If she sold 70 pens, how many pencils did she sell?​

Answers

Answered by charvisharma9b9212
6

Answer:

The correct option is A 175

There is neither profit nor loss.

Profit earned + loss incurred = 0

i.e., Profit earned = - Loss incurred.

Now, Profit earned by selling 70 pens = 70 × 1 = ₹ 70

Therefore, Loss incurred by selling pencils = - ₹ 70 or - 7000 paise.

Loss incurred on each pencil = 40 paise.

Hence, total number of pencils sold =

(Total loss incurred)

(Loss on each pencil)

=

7000

40

= 175 pencils

Answer: (A) 175

Answered by ItzBlinks
5

(i) profit earned by selling one pen= ₹ 1

profit earned by selling 45 pens = to ₹45, which we donate by +₹45

total loss given=to ₹ 5, which we donate by - ₹5

profit earned+ loss incurred = total loss

therefore ,loss incurred = total loss- profit earned = ₹ (-5-45)=₹ (-50)= -5000 paise

loss incurred by selling one pencil= (-5000) ÷(-40)=125

(ii) In the next month there is neither

profit nor loss.

So, profit + Loss incurred =0

Profit earned= -Loss incurred.

Now, profit earned by selling 70pens.

Hence, loss incurred by selling pencils=

₹ 70 which we indicate by -₹70 or -7000 paise.

Total number of pencil sold=(-7000)÷(-40)

=175 pencils.

Hope it's helpful ☺️

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