Math, asked by lsecafe2014, 10 months ago

A shopkeeper earns a profit of Rs 1 by selling one pen and Incurs a loss of 40 paise per
pendl while selling pencils of her old stock. In a particular nonth she incurs a loss of Rs
5. In a month she earns neither profit nor loss. If she sold 70 pens, how many pencils did
she sell?​

Answers

Answered by lucksri789
2

Answer:

ANSWER

Profit earned by selling 1 pen = Re 1

Profit earned by 45 pens = Rs. 45, which we denote by + Rs. 45

Total loss given = Rs. 5, which we denote by Rs -5.

Profit earned + Loss incurred = Total Loss

Therefore, loss incured = Total Loss - Profit earned.

= Rs. (-5-45)

=Rs. (-50)= -5000 paise

Loss incurred by selling one pencil = 40 paise, which we write as -40 paise.

So, number of pencils sold = (−5000)÷(−40)=125 pencils.

Answered by PihuChugh
0

Answer:

187 pencils

Step-by-step explanation:

here, we donate

profit by +

loss by -

according to question

profit on 1 pen= +1 rupees= +100 paise

loss on 1 pencil= -40 paise

total loss = -5 rupees

-5 * 100 paise

-500 paise

number of pens sold = 70*100 paise

7000 paise

also,

loss on pencil sold = (-40) * no. of pencils sold

now,

total loss = (-40) * no. of pencils

-500 = 7000 + (-40) * no of pencils sold

-500 - 7000 = (-40) * no. of pencils sold

-(500 + 7000) = (-40) * no. of pencils sold

-7500 = (-40) * no. of pencils sold

-7500/-40 = no. of pencils sold

187 = no. of pencils sold

therefore , no of pencils sold are 187

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