Question

A shopkeeper first raises the price of Jewellery by x% then he decreases the new price by x%. After such up down cycle, the price of a Jewellery decreased by Rs. 21025. After a second up down cycle the Jewellery was sold for Rs. 484416. What was the original price of the jewellery.2
A.Rs. 5,26,000
B.Rs. 6,00,625
C.Rs. 525625
D.Rs. 5,00,000

Answer 1

______✨ HEY MATE ✨_______

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SOLUTION:-
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Let the initial price = Rs. 10000P
price after first increment = 10000P + 100xP.
price after first decrement = 10000P + 100xP - (100Px+Px2) = 10000P - Px2.
Now, total decrement,
Px2 = 21025 .............. (1)

price after second increment,
10000P - Px2 + 100xP - Px3/100
price after second increment,
10000P - P2 + 100xP - P3/100 - 100xP + Px3/100 - Px2 + Px4/10000
= 10000P -2Px2+Px2/10000 = 484416 ............... (2)

on solving equation equn (1) and (2), We get
x = 20.
substituting back we get,
P = 52.5625
Therefore.

So , Option (C) 52.5625 is the right answer ✔️

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Answer 2

_____✨ HEY MATE ✨_______

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SOLUTION:- 
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Let the initial price = Rs. 10000P
price after first increment = 10000P + 100xP.
price after first decrement = 10000P + 100xP - (100Px+Px2) = 10000P - Px2.
Now, total decrement,
Px2 = 21025 .............. (1)

price after second increment,
10000P - Px2 + 100xP - Px3/100
price after second increment,
10000P - P2 + 100xP - P3/100 - 100xP + Px3/100 - Px2 + Px4/10000
= 10000P -2Px2+Px2/10000 = 484416 ............... (2)

on solving equation equn (1) and (2), We get
x = 20.
substituting back we get,
P = 52.5625
Therefore.

So , Option (C) 52.5625 is the right answer ✔️

✌️I THINK IT HELPED YOU ✌️