Math, asked by aks471, 1 month ago

A shopkeeper fixed the price of a pen to make a profit of 10 %. But he sold it
allowing a discount of Rs 7.50 and lost 5 %. At what price did he purchase the
pen?

Answers

Answered by amitbobbypathak
0

Answer:

Selling Price fixed at 1.10CP for a 10% Profit

Profit=[SP-CP]/CP

0.10=[1.10CP-CP]/CP=0.10CP/CP=0.10 Ok

At Rs 7.50 discount the profit is 5% loss from 10% profit, thus the profit becomes 5% only:

0.05=[(1.10CP-7.50)-CP]/CP

0.05CP=0.10CP-7.50

0.05CP-0.10CP=-7.50

-0.05CP=-7.50

CP= -7.50/-0.05= Rs 150 purchased price or cost price

Check:

At 10% profit, Selling Price is 1.10(150)= Rs 165

0.10=(165–150)/150=15/150=0.10 ok

at a discount of Rs 7.50 and a profit loss of 5%, so the selling price is 165–7.50=Rs157.50 and the profit is only 5% or 0.05 for the cost price of Rs 150:

0.05=[157.50– 150]/150=7.50/150= 0.05

Step-by-step explanation:

Answered by khushi6227
0

Answer:

so here is your answer

step by step explaination

Step-by-step explanation:

please Mark as Brainlist

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