Question

a shopkeeper gains rupees 2 on each pen and loses rupees 1 on each pencil he self 45 pens and some pencils losing rupees 10 in all . how many pencils does he sell?​

Answer 1

Answer:

No. of pen sells=45

therefore profit = 45×1=45rs.

loss on x pencil = x ×.40=0.40x rs.

a/q. = 0.40x-45rs=5

0.40x = 50rs

x=50/0.40

=125

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Answer 2

$\sf \: The \: amount \: of \: profit \: earned \: in \: \\ \sf selling \: 1 \: pen \: is \: Re \: 1$

$\mapsto \sf The \: amount \: of \: profit \: earned \: in \: \\ \sf selling \: 45 \: pen \: is \: Re. \: 1 \: x \: 45 = \: \: 45$

Hence, the profit earned is Rs. 45

The net loss he suffered in selling pencil is Rs. 5.

• $\sf The \: loss \: in \: transaction \: is \: loss: =-Rs.5 \: - Rs. \: 45 \: =-Rs.50 \: =-5000 \: paise$

Loss incurred in selling 1 pencil =- 40 paise

The number of pencil sold by the shopkeeper is 5000/40 = 125 pencils

• Hence, the number of pencil sold by the shopkeeper is 125 pencils.

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