A shopkeeper gives books on rent for reading. She takes a fixed charge for the first two days and an additional charge for each day thereafter. Latika paid Rs. 22 for a book kept for six days, while Anand paid Rs. 16 for the book kept for 4 days. Find the fixed charges and the charge for each extra day
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Latika
2(FC)+4(AC)
2x+4y=22
Anand
3x+y=16
2(FC)+4(AC)
2x+4y=22
Anand
3x+y=16
Answered by
3
Let Latika takes a fixed charge for the first two day is ₹x and additional charge for each day thereafter is ₹y.
Now by first condition.
Latika paid ₹22 for a book kept for six days
x+4y = 22 .......(1)
and by second condition ,
Anand paid ₹16 for a book kept for four days
x+2y = 16 ........(2)
Now , subtracting eq(1) from eq (2), we get
2y = 6
y = 3
On putting the value of y in eq (2), we get
x+2×3 = 16
x = 16-6
x = 10
Fixed charge = ₹10
The charge for each extra day = ₹3
HOPE IT HELPS U.....
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