Question

A shopkeeper has 1200 articles. he wants to pack the articles in such a way that the number of articles in a box and the number boxes remain same . find how many more articles he needs for this .​

Answer 1

Answer:

let the shopkeeper bought x number of books for Rs.1200

price for each book = 1200/x

If he had bought 10 more books for the same amount each book would have cost Rs 20 less

it means

the cost of each books is decreased by 20 if he had bought 10 more books

I.e.

ATQ

1200/x - 1200/x + 10 = 20

1200(1/x - 1/(x+10) = 20

1/x - 1/x+10 = 20/1200

(x+10) - x /x(x+10) = 1/60

x+10 -x = x² + 10x / 60

600 = x² + 10x

x² + 10x - 600 = 0

Here quadratic equation formed ...

x² + 10x - 600 = 0

x² + 30x - 20x - 600 = 0

x(x+30) -20(x+30) = 0

(x+30) (x-20) = 0

either

(x+30) =0 or (x-20) = 0

x = -30 or x = 20

x = -30 X not possible because the number of books cant be negative

so number of books = x = 20

Step-by-step explanation:

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