Question

a shopkeeper has 1442 toys in his shop. if he sold all the toys in 87 days then find the number of tous sold in a day. also estimate quotient to the nearest 10's please this is five mark question write in word problem​

Answer 1

$\huge\red{AN}\pink{S}\orange{W}\green{E}\blue{R}$

Solution:

Let the number toys be xy. which can be written as 10x+y.

where, y is the digit of units place and x is the digit of tens place.

And price of each toy =ab  which can be written as 10a+b.

where, b is the digit of units place and a is the digit of tens place.

Now, 

A/q , the shopkeeper has 81 items more than actual.

10x+y=10y+x+81

or, 9x−9y=81

or, x−y=9

The only possible solution of above equation is x=9 and y=0.

So, actual number of toys sold =90 

The wrongly recorded number of toys sold =9

∴ Wrongly recorded selling price of a toy =9Rs.882=Rs.98

So, the correct selling price of a toy =Rs.89

Answer 2

Answer:

Let the number toys be xy. which can be written as 10x+y.

where, y is the digit of units place and x is the digit of tens place.

And price of each toy =ab  which can be written as 10a+b.

where, b is the digit of units place and a is the digit of tens place.

Now, 

A/q , the shopkeeper has 81 items more than actual.

10x+y=10y+x+81

or, 9x−9y=81

or, x−y=9

The only possible solution of above equation is x=9 and y=0.

So, actual number of toys sold =90 

The wrongly recorded number of toys sold =9

∴ Wrongly recorded selling price of a toy =9Rs.882=Rs.98

So, the correct selling price of a toy =Rs.89

Hence, A is the correct answer

Step-by-step explanation:

hope this helps you