A shopkeeper has 2783 notes of 50 and 4832 notes each of 20. What is the total amount with him ?
Answers
Answer:
235,790
Step-by-step explanation:
2783×50
=139,150
4832×20
=96,640
=139,150+96,640
=235,790
Answer:
Let C.P. of table = Rs x and
C.P. of chair = Rs y
The shopkeeper sells the table at 8% profit and the chair at 10% discount
⇒x×
100
108
+y×
100
90
=1008
⇒108x+90y=100800
⇒6x+5y=5600 …(i)
The shopkeeper sells the table at 10% profit and the chair at 8% discount and got Rs.20 more.
⇒x X 100
110
=1008+20
⇒110x+92y=102800
⇒55x+46y=51400
Now, multiplying (i) by 55 and (ii) by 6, we have
330x+275y=308000
330x+276y=308400
Subtracting equation (iv) from (iii), we get
⇒−y=−400
⇒y=400
On substituting the value of y in equation (i), we get
⇒6x+5(400)=5600
⇒6x=5600−2000
⇒x= 3600/6
⇒x=600
Hence, Cost Price of the table = Rs 600
List price of chair =400×
= Rs 360
Step-by-step explanation: