A shopkeeper has 50 kg sugar. He sells ( 1/7 ) th of it at ₹ 21 per kg, (3/7) th of it at ₹35 per kg, and remaining at ₹ 35 per kg. how much money did he collect ?
Answers
A shopkeeper has 50 kg sugar. He sells (1/7 th of it at ₹21bper kg,
The total money collected is Rs.1,650.
Given:
The price of 1/7th sugar=₹ 21 per kg
The price of 3/7th sugar=₹35 per kg
The price of the remaining sugar=₹ 35 per kg
Amount of sugar=50kg
To find:
The total money collected
Solution:
The total money earned can be calculated by obtaining the amount earned by selling 1/7th, 3/7th and the remaining sugar.
The amount of 1/7th sugar=1/7 of 50 kg=50/7 kg
The amount of 3/7th sugar=3/7 of 50 kg=150/7 kg
The remaining sugar=(1-1/7-3/7)=(1-4/7)=3/7th sugar
=3/7 of 50 kg=150/7 kg
Now, the total amount earned=quantity of sugar×price
=(50/7×21)+(150/7×35)+(150/7×35)
=(50×3)+(150×5)+(150×5)
=150+750+750
=Rs.1,650
Therefore, the total money collected is Rs.1,650.