Question

A shopkeeper has ball of jute of 15 m if he sell 2 1/4 to one customer and 3 1/4 tos econd customer what length of jute left with him

Answer 1

Step-by-step explanation:

Let x meter of jute left with the shopkeeper.

Therefore,

$2 \frac{1}{4} + 3 \frac{1}{4} + x = 15 \\ \frac{2 \times 4 + 1}{4} + \frac{3 \times 4 + 1}{4} + x = 15 \\ \frac{8 + 1}{4} + \frac{12 + 1}{4} + x = 15 \\ \frac{9}{4} + \frac{13}{4} + x = 15 \\ \frac{9 + 13}{4} + x = 15 \\ \frac{22}{4} + x = 15 \\ \frac{11}{2} + x = 15 \\ x = 15 - \frac{11}{2} \\ x = \frac{15 \times 2 - 11}{2} = \frac{30 - 11}{2} \\ x = \frac{19}{2} \\ x = 9 \frac{1}{2} \\Hence, 9 \frac{1}{2} \: metre \: length \: of \: jute \: \\ ball \: is \: left \: with \: shopkeeper.$