a shopkeeper has some pens out of which 1/3rd are blue , 1/4th are black and the remaining are green . If he has 10 green pens, how many does he have in total.
Answers
Answer:
∴ The shopkeeper has pens.
Step-by-step explanation:
- In context with question asked,
- We have to find total number of pens.
- Let, be the total number of pens.
- It is given that, number of blue pens =
Number of blue pens =
Number of black pen =
- Now, according to given condition, the equation becomes,
Total number of pens = Number of blue pen + black pens + green pens
∴
- LCM of and is .
- Equating the denominators, we get
∴
∴
∴
∴
∴
∴
∴
∴
- ∴ Number of blue pens = = pens
Number of blue pens = pens
- ∴ The shopkeeper has pens.
Shopkeeper has 24 pens in Total if 1/3rd are blue , 1/4th are black and the remaining 10 are green
Given:
- A shopkeeper has some pens
- 1/3rd are blue
- 1/4th are black
- remaining 10 pens are green
To Find:
- Total number of pens
Solution:
Step 1:
Assume that shopkeeper has 12x pens
Step 2:
Calculate the number of blue pens
= (1/3)12x
= 4x
Step 3:
Calculate the number of black pens
= (1/4)12x
=3x
Step 4:
Add black , blue and green pens and equate with total pens to solve for x
4x + 3x + 10 = 12x
=> 7x + 10 = 12
=> 10 = 5x
=> 2 = x
Step 5:
Use x = 2 and calculate 12x
12x = 12(2) = 24
Shopkeeper has 24 pens in Total