Question

A shopkeeper has three cakes of weight 10 kg, 20 kg, and 15 kg. If he wants to cut these cakes into pieces of equal weight without any wastage, the maximum possible weight of each piece is , everyone knows the answer

Answer 1

Answer:

Step-by-step explanation:

so we need to find the hcf of 10,20 and 15

we can do this by prime factorisation

10=2*5

20=2*2*5

15=3*5

so the hcf would be 5 as 5 is a multiple of all three numbers

so the maximum possible weight of each piece would be 5 kg

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