Question

A shopkeeper has three cakes of weights 18 kg 45 kg and 36 kg. If he wants to make this cakes into pieces of equal weight without wastage , what is the maximum possible weight of each question ( ans:9kg)​

Answer 1

Answer:

HCf of 18,45, & 36 is 9

so 9kg is the answer

Answer 2

Answer:

The maximum possible weight is 9 kg.          

Step-by-step explanation:

Given : A shopkeeper has three cakes of weights 18 kg 45 kg and 36 kg. If he wants to make this cakes into pieces of equal weight without wastage.

To find : What is the maximum possible weight?

Solution :

To find the maximum possible weight we find the highest common factor of the given weights.

A shopkeeper has three cakes of weights 18 kg 45 kg and 36 kg.

Prime factors of the weights are

$18=2\times 3\times 3$

$45=3\times 3\times 5$

$36=2\times 2\times 3\times 3$

$HCF(18,45,36)=3\times 3$

$HCF(18,45,36)=9$

Therefore, The maximum possible weight is 9 kg.