Question

A shopkeeper has to completely pack each of three types of grains weighing 403 kg of Rice, 465 kg of Wheat and 496 kg of Corn in the packets of equal sizes without mixing any of them such that each packet is completely filled. What is the least number of packets required by the shopkeeper?​

Answer 1

Answer:

the least number of packets required by the shopkeeper is 44

Explanation:

To find the number of packets,

HCF Of 403, 465, 496

403= 13 × 31

465= 3×5×31

496= 2×2×2×2×31

Hence, common factor =31

So, HCF = 31

Now,

total weight of grains =(403 +465 +496)= 1364kg

Therefore,

number of packets required = 1364÷31 =44