Question

a shopkeeper has two pieces of rope having length 120 and 150 cm we want to cut the ropes into pieces of equal length as long as possible what should be the length of each piece​

Answer 1

factors of 120=2,2,2,3,5

factors of 150=2,3,5,5

common factors=2,3,5

hence, HCF=30

therefore,

possible equal length should cut is 30cm