Question

A shopkeeper has two types of a mixture of tea. In 48 kg of the
first mixture ratio of tea to impurity is 5:3 and in 42 kg of the
second mixture ratio of tea to impurity is 3 : 1. If the shopkeeper
mixes these two mixtures with 56 kg of pure tea in a large
container, then find the ratio of tea to impurity in the container?​

Answer 1

Answer:

good question keep it up

Answer 2

Answer:

let the ratio be  X

Step-by-step explanation:

5x + 3x = 48

8x =48

x= 48/8

=6 = x

so 5 * 6 =30

    3 * 6 =18

second tea mixture

let ratio be x

3x + 1x = 42

4x = 42

x = 42/4

x = 2.625

so 3 * 2.625  =  6.25

    1  * 2.625 =2.625