A shopkeeper has two types of a mixture of tea. In 48 kg of the
first mixture ratio of tea to impurity is 5:3 and in 42 kg of the
second mixture ratio of tea to impurity is 3 : 1. If the shopkeeper
mixes these two mixtures with 56 kg of pure tea in a large
container, then find the ratio of tea to impurity in the container?
Answers
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Answer:
good question keep it up
Answered by
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Answer:
let the ratio be X
Step-by-step explanation:
5x + 3x = 48
8x =48
x= 48/8
=6 = x
so 5 * 6 =30
3 * 6 =18
second tea mixture
let ratio be x
3x + 1x = 42
4x = 42
x = 42/4
x = 2.625
so 3 * 2.625 = 6.25
1 * 2.625 =2.625
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