Math, asked by khushirathore025, 1 month ago

A shopkeeper increases the price of a pencil by 50 paise and that of an eraser by 75 paise every year. If in 2005 the price of a pencil was ₹5.75 and the price of an eraser was ₹4.25, then in which year was the price of a pencil 50 paise more than the price of an eraser

Answers

Answered by EmeraldLady
72

\bigstar \: \boxed{\sf{\color{purple}{Question:}}}

A shopkeeper increases the price of a pencil by 50 paise and that of an eraser by 75 paise every year. If in 2005 the price of a pencil was ₹5.75 and the price of an eraser was ₹4.25, then in which year was the price of a pencil 50 paise

more than the price of an eraser?

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\bigstar \: \boxed{\sf{\color{purple}{Answer:}}}

❍ Selling :

By selling a pen gain is Rs.2

and by selling a pencils, he loses 50 paise

and an eraser, he loses 15 paise

On one day, he gain =Rs.10

❍ Calculation :

On that day he sold 10 pens and pencils and erasers in the ratio of 7:10

On ten pens, his gain =10×2=Rs.20

❍ Loss :

loss on pencils and erasers =Rs.20−Rs.10=Rs.10=1000 paise

Ratio in pencil and eraser =7:10

Let, it be

Let number of pencils =7x, then eraser =10x

7x×50+10x×15=1000

⇒350x+150x=1000

⇒500x=1000

⇒x=2

Numbe rof penciles =7×2=14

and number of erasers =10×2=20

❍ Hence, Proved!

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