A shopkeeper marked up an article 40% above its CP and allowed 2 successive discounts of d% and 25% respectively on it. If shopkeeper made a loss of 16% on the SP of the article. then find 'd'
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Answer:
let CP of the article = Rs. 100x
Let the MP of the article = 100x × (140/100) = Rs. 140x
SP of the article after getting two successive discount of 20% and 25% = 140x × (80/100) × (75/100) = Rs. 84x
Loss = 100x - 84x = 16x
16x = 140
x = 140/16
CP of the article = 140/16 × 100 = Rs. 875
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Answer: d is 20% discount
Step-by-step explanation:
Let, cp is x rs
Marked price is (100+40)x/100 = 1.4x rs
After 1st discount,
Selling price = (100- d)×1.4x/100 = 0.014(100-d)x rs
After 2nd discount,
Selling price = (100-25)/100 × 0.014(100-d)x = 0.0105(100-d)x
Now, loss on sp = (100-16)×x/100 = 0.84x
Now, 0.0105(100-d)x = 0.84x
, 100-d = 0.84/0.0105 = 80
, d = 20%
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