a shopkeeper marks his goods at 25% more than their cost price and allows a discount of 10%. Find his gain or lose percent
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Answer :-
For answering such questions here I give you a short cut method -
Gain or loss percent = X + Y +(X×Y)/100
For increase use positive sign and for decrease use negative sign.
So here, X = +25%
And Y = -10% negative as it is discount
Put the values of X and Y in the above formula, if solution is positive it is gain and if it is negative it is loss
=25+(-10) +(25×-10)/100
=25 -10 -250/100
=25–10–5/2
=15-5/2
=12.5
It is positive so there will be profit of 12.5% in this transaction.
For answering such questions here I give you a short cut method -
Gain or loss percent = X + Y +(X×Y)/100
For increase use positive sign and for decrease use negative sign.
So here, X = +25%
And Y = -10% negative as it is discount
Put the values of X and Y in the above formula, if solution is positive it is gain and if it is negative it is loss
=25+(-10) +(25×-10)/100
=25 -10 -250/100
=25–10–5/2
=15-5/2
=12.5
It is positive so there will be profit of 12.5% in this transaction.
andy75:
thanx a lot
Answered by
0
Answer:
Sol. Let the C.P=50
M.P=50+25%of 100= Rs 75
Discount=10%
:;' Discount (in Rs)=10%of 150
=75×10/100=Rs 7.5
:;. S.P=M.P- discount
=75-7.5=67.5
S.P>C.P
gain =s.p-c.p
=67.5-50=17.5
profit %=profit/C.P×100
=17.5/50×100
=17.5×2 =35% answers
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