Math, asked by dhanasekartool, 11 months ago

A shopkeeper mixes 20 kgs of rice which cost Rs. 5 per kg with 35 kg of rice which cost Rs. 7 per kg. Then he sells the mixture at Rs. 6.50 per kg. Find his profit percentage.
A) 3% B) 3+40/67 % C) 4+34/69 % D) 3+43/69 %
Please explain for step by step...

Answers

Answered by kvkeerthana
1

Answer:

Option a is correct.

Step-by-step explanation:

Cost of 1 kg of rice = 5

Cost of 20 kg of rice = 20 × 5 = 100

Cost of 1 kg of another rice = 7

Cost of 35 kg of another rice = 35 × 7 = 245

Total kg of both rice = 35 + 20 = 55 kg

Total cost of 55 kg of two rices = 245 + 100 = 345

Cost of i kg of the mixed rice = 345/55 = 6.27

SP of the mixed rice = 6.50

Profit money per kg  = 6.50 - 6.27 = 23 paise = 0.23

Profit money of 55 kg = 6.50 × 55 = 357.5 - 345 = 12.5

Profit % = 12.5/345 × 100

            = 3.623%

Option a is correct.

                  HOPE IT HELPS U!

               MARK AS BRAINLIEST!

Answered by maheshsenthil31
0

Answer:

Step-by-step explanation:

20 kg× 5 = ₹100

35 kg × 7 = ₹245

Total = ₹345

Total kg = 55

Now one kg sell = ₹6.50

55 × 6.50 = 357.5

Difference = ₹12.5 profit

Profit % = 12.5 / 345 × 100 = 1250/345

= 3 215/345 %

= 3 43/69 % #Ans

Similar questions