A shopkeeper mixes 60 kg of sugar worth Rs.
30 per kg with 90 kg of sugar worth Rs. 40
per kg. At what rate he must sell the mixture
to gain 20%?
Answers
Answer:
rs 43.2
Step-by-step explanation:
total kgs = 60+90= 150kgs
TOTAL Cost price = (30* 60)+(40*90)
= 1800+ 3600
=rs. 5400/-
now we have to take cost price for 1kg,
= total cost/ total kg
= 5400/150
CP =rs. 36/kg
take CP as 100%,
profit = 20% .so,it will be 20% more than CP. i.e., 120%
100% = 36
120% = x
apply cross multiplication method,
x= 43.2 rs
Given : A shopkeeper mixes 60 kg of sugar worth Rs.
60 kg of sugar worth Rs.30 per kg with 90 kg of sugar worth Rs. 40 per kg.
To find : At what rate he must sell the mixture to gain 20%?
Solution :
We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the rate of selling)
Now, cost price of 60 kg sugar worth Rs. 30 per kg :
= (Amount of sugar × Price rate)
= Rs. (60 × 30)
= Rs. 1800
Now, cost price of 90 kg sugar worth Rs. 40 per kg :
= (Amount of sugar × Price rate)
= Rs. (90 × 40)
= Rs. 3600
If he mixes the two types of sugar, then the total cost price of the entire mixture :
= Cost price of 60 kg sugar worth Rs. 30 per kg + Cost of 90 kg sugar worth Rs. 40 per kg
= Rs. (1800 + 3600)
= Rs. 5400
Now, total amount of mixture = (60 + 90) = 150 kg
Cost price of 1 kg of the mixture :
= Total cost price of the mixture ÷ Total amount of mixture
= Rs. (5400 ÷ 150)
= Rs. 36
Now, he needs to gain 20% while selling the sugar. Which means he needs 20% profit while selling the sugar.
So, the profit amount will be :
= Cost price of 1 kg of the mixture × 20%
= Rs. (36 × 20%)
= Rs. [36 × (20/100)]
= Rs. 7.2
The selling price of 1 kg of the mixture will be :
= Cost price of 1 kg of the mixture + Profit amount
= Rs. (36 + 7.2)
= Rs. 43.2
(This will be considered as the final result.)
Hence, he must sell the mixture at Rs. 43.2 per kg to gain 20%.